johnniedavila87 johnniedavila87
  • 23-02-2016
  • Mathematics
contestada

How many terms are in the arithmetic sequence 1313, 1616, 1919, ……, 7070, 7373?

Respuesta :

taskmasters
taskmasters taskmasters
  • 02-03-2016
To find the number of terms in the arithmetic sequence, we need to use the formula 
[tex] a_{n}= a_{1}+(n-1)d [/tex]    
where [tex] a_{n} [/tex] is the nth number, [tex] a_{1} [/tex] is the first number, n is the number of terms and d is the difference of the two consecutive numbers.
7373 = 1313 + (n - 1)(303)
7373 = 1313 + 303n - 303
7373 = 1010 + 303n
7373 - 1010 = 303n
6363 = 303n
6363 ÷ 303 = n
n = 21

Therefore, there are 21 terms in the arithmetic sequence given.
Answer Link

Otras preguntas

how do you simplify 681
How many times more basic is a solution with a pH of 10 than a solution with a pH of 8  a. A pH of 10 is two times as basic  b. A pH of 8 is two times as basic
Graph the linear equation solve for Y 3x+y=6
What does a red shift indicate about a galaxy? A. It is moving toward Earth. B. It is moving very fast. C. It is slowing down. D. It is moving away from Earth.
What's 32xy divided by 24yz and how do you figure it out.  The question also asks me to write it as a fraction then cancel (or reduce).
write 6/10 as a terminating decimal
how do you simplify 681
how can you tell that a fraction corresponds to a repating decimal and not a terminating decimal
Two fifths the cube of a number
which  property should be used next in this solution process 3x+2+3=7(x-1)-4