khan509 khan509
  • 21-05-2018
  • Mathematics
contestada

How do you write the vertex form equation of the parabola #y=2x^2 +11x-6#?

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altavistard
altavistard altavistard
  • 23-05-2018
The easist way to find the vertex is to complete the square:

y=2x^2 +11x-6  =>  y=2[ x^2 + (11/2)x  + (11/2)^2   - (11/2)^2 ]  - 6  

This can be rewritten as 
                                y = 2[(x+11/2)^2 ] -(121/4) - 24/4

                                y = 2 (x+11/2)^2 - 145/4

this is the equation in vertex form.  The vertex is at (-11/2, -145/4).
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