Answer:
The correct answer is option B.
Step-by-step explanation:
Given function ;
[tex]y =2x^2+7x+3[/tex]
In order to determine the zeros of function , put y = 0:
[tex]0=2x^2+7x+3[/tex]
Using mid-therm theorem ;
[tex]2x^2+1x+6x+3=0[/tex]
[tex]x(2x+1)+3(2x+1)=0][/tex]
[tex](2x+1)(x+3)=0[/tex]
1) (2x+1)= 0
[tex]x=-\frac{1}{2}[/tex]
2) x +3 = 0
[tex]x = -3[/tex]
