Hi there!
Let x = 3. 72727.... ---(i)
Multiply 100 in eqn. (i)
100x = 372. 72727... ---(ii)
Subtract Eqn. (i) from (ii)
100x - x = 372. 7272... - 3. 7272...
99x = 369
x = [tex]\dfrac {369}{99}[/tex]
x = [tex]\dfrac {41}{11}[/tex]
Hence, [tex]\dfrac {41}{11}[/tex] is th' required p-q form.
~ Hope it helps!
