Answer:
Phase angle is 50.527°
Step-by-step explanation:
Given that in a parallel circuit [tex]E_{T}=277V[/tex], R=56kΩ and [tex]X_{L} =[/tex]68kΩ.
And we are asked to find phase angle.
In any circuit, phase angle[tex]\theta=tan^{-1}(\frac{X_L-X_C} {R})[/tex]
Since we don't have any capacitor,[tex]X_{C}=0[/tex]
Hence phase angle,[tex]\theta=tan^{-1}(\frac{68000}{56000})[/tex]
[tex]=tan^{-1}(1.2143)[/tex]=50.527°≈50.53°
