Respuesta :

lublana

Given equation is x+3y=27.

Now question says to find the x-intercept and y-intercept.

We know that x-intercept is the x-value when y=0

so plug y=0 into given equation and solve for x

x+3y=27

x+3*0=27

x+0=27

x=27

Hence x-intercept is at (27,0)

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We know that y-intercept is the y-value when x=0

so plug x=0 into given equation and solve for y

x+3y=27

0+3y=27

3y=27

y=9

Hence y-intercept is at (0,9)

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Hence final answer is the first choice