jenn2fur005
jenn2fur005 jenn2fur005
  • 25-02-2019
  • Mathematics
contestada

no one is helping me, can you please help me?​

no one is helping me can you please help me class=

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jimthompson5910 jimthompson5910
  • 25-02-2019

Answer: Choice (4) which is y > 0

======================================

Explanation:

As x heads off to negative infinity, the value of y = 4^x slowly approaches y = 0. It never actually gets to y = 0 even if it looks like it might.

Note that for negative x values, y = 4^x is going to involve a fraction

Example: if x = -2 then y = 4^x = 4^(-2) = 1/(4^2) = 1/16 = 0.0625

So this means that y can be any positive number with 0 being the boundary or fence it runs into. This "fence" is the horizontal asymptote.

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