Answer: [tex]\bold{(20x)^{\frac{1}{12}}=(\frac{4}{5})^y}[/tex]
Step-by-step explanation:
[tex]log_{\frac{4}{5}}(20x)=12y\\\\\text{divide 12 from both sides:}\quad \frac{1}{12}log_{\frac{4}{5}}(20x)=y\\\\\text{condense log (coefficient converts to exponent):}\quad log_{\frac{4}{5}}(20x)^{\frac{1}{12}}=y\\\\\text{use log rules to convert log to exponential form:}\quad (20x)^{\frac{1}{12}}=(\frac{4}{5})^y[/tex]
