jarantebolds201
jarantebolds201 jarantebolds201
  • 26-02-2019
  • Mathematics
contestada

Which is the completely factored form of f(x) = x^3 - 2x^2 - 5x + 6?

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Аноним Аноним
  • 26-02-2019

Answer:

(x - 1)(x - 3)(x + 2).

Step-by-step explanation:

f(1) = 1^3 - 2(1)^2 - 5(1) + 6

= 1 - 2 - 5 + 6

= 0

so one factor is (x - 1)  (by the Factor Theorem).

Divide f(x) by x - 1 we get:

x- 1) x^3 - 2x^2 - 5x + 6 (  x^2 - x - 6 <------ answer

       x^3 - x^2

              -x^2 - 5x

              -x^2 + x

                       -6x + 6

                        -6x + 6

= x^2  - x - 6  

= (x - 3)(x + 2).

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