hannabdavis2004 hannabdavis2004
  • 22-03-2019
  • Mathematics
contestada

What is the surface area of a right circular cylinder with a height of 8 meters and a base whose
radius is 4 meters?
(A)144 m2 (B)96 m2 (C)80 m2 (D)128 m2

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 31-03-2019

Answer:

[tex]S.A=96\pi m^2[/tex]

Step-by-step explanation:

The surface area of a right circular cylinder is given by the formula;

[tex]S.A=2\pi r(r+h)[/tex]

where [tex]h=8m[/tex] is the height of the cylinder and

[tex]r=4m[/tex] is the radius of the cylinder.

We plug in these values into the formula to obtain;

[tex]S.A=2\pi \times4(4+8)[/tex]

[tex]S.A=8 \times12 \pi[/tex]

[tex]S.A=96\pi m^2[/tex]

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