kyleemoryowwcrq kyleemoryowwcrq
  • 25-03-2019
  • Mathematics
contestada

8..................................

8 class=

Respuesta :

Ashraf82
Ashraf82 Ashraf82
  • 25-03-2019

Answer:

The answer is [tex]2x^{3}y^{-2}\sqrt{6}[/tex]

Step-by-step explanation:

∵ √24 = 2√6

∵ [tex]\sqrt{x^{6}}=(x^{\frac{1}{2}})^{6}=x^{3}[/tex]

∵ [tex]\sqrt{y^{-4}}=(y^{\frac{1}{2}})^{-4}=y^{-2}[/tex]

∴ [tex]\sqrt{24x^{6}y^{-4}}=2x^{3}y^{-2}\sqrt{6}[/tex]

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