herethan6162 herethan6162
  • 26-03-2019
  • Mathematics
contestada

What are the zeros of g(x)=(3x-1)(2x+5)(7x-14)^2
ANSWER ASAP BY THE END OF THE DAY WITH THE WORK. PLZ!

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jimrgrant1 jimrgrant1
  • 26-03-2019

Answer:

see explanation

Step-by-step explanation:

To find the zeros equate g(x) to zero, that is

(3x - 1)(2x + 5)(7x - 14)² = 0

Equate each factor to zero and solve for x

3x - 1 = 0 ⇒ 3x = 1 ⇒ x = [tex]\frac{1}{3}[/tex]

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = - [tex]\frac{5}{2}[/tex]

(7x - 14 )²  = 0 ⇒ 7x - 14 = 0 ⇒ x = 2 with multiplicity 2

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