ANSWER
[tex]( {x - 11)}^{2} + ( {y - 5)}^{2} = 16[/tex]
EXPLANATION
The given circle has center:
(11,5)
and
radius: 4
The equation of a circle with center (h,k) and radius , r is given in standard form as;
[tex]( {x - h)}^{2} + ( {y - k)}^{2} = {r}^{2} [/tex]
We substitute the values into the formula to obtain,
[tex]( {x - 11)}^{2} + ( {y - 5)}^{2} = {4}^{2} [/tex]
[tex]( {x - 11)}^{2} + ( {y - 5)}^{2} = 16[/tex]
