Respuesta :

chibigamerk12

Answer:

(f - g)(x) = (3x + 1) - (x2 - 6) = 3x + 1 - x2 + 6 = -x2 + 3x + 7

i hope this helps.

carlosego

For this case we have the following functions:

[tex]f (x) = 3x + 1\\g (x) = x ^ 2-6[/tex]

We must find[tex](f-g) (x).[/tex]

By definition we have to:

[tex](f-g) (x) = f (x) -g (x)[/tex]

So:

[tex](f-g) (x) = 3x + 1- (x ^ 2-6)\\(f-g) (x) = 3x + 1-x ^ 2 + 6\\(f-g) (x) = - x ^ 2 + 3x + 6 + 1\\(f-g) (x) = - x ^ 2 + 3x + 7[/tex]

Answer:

[tex](f-g) (x) = - x ^ 2 + 3x + 7[/tex]