Answer: [tex]\bold{(0,-\sqrt{26})\quad \&\quad (0,\sqrt{26})}[/tex]
Step-by-step explanation:
[tex].\qquad y^2-25x^2=25\\\\\implies \dfrac{y^2}{25}-\dfrac{25x^2}{25}=\dfrac{25}{25}\\\\\\\implies \dfrac{y^2}{25}-\dfrac{x^2}{1}=1\\\\\\Center: (0, 0)\\Length\ of\ foci:25+1=c^2\implies \sqrt{26}=c\\Foci: (0,0\pm \sqrt{26})[/tex]
