atkmanny atkmanny

24-07-2019
Mathematics

contestada

How many combinations without repetition are possible if n = 5 and r = 3?

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konrad509 konrad509

24-07-2019

[tex]_nC_r=\dfrac{n!}{r!(n-r)!}\\\\_5C_3=\dfrac{5!}{3!2!}=\dfrac{4\cdot5}{2}=10[/tex]

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ZerbeM262 ZerbeM262

21-04-2021

Answer:

10

Step-by-step explanation:

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