summeraspen51 summeraspen51
  • 25-09-2019
  • Mathematics
contestada

if y varies direrectly as x and inversely as the square of z. y=52 when x=16 and z=2. find y when x=18 and z=3.

Respuesta :

jimrgrant1 jimrgrant1
  • 25-09-2019

Answer:

y = 26

Step-by-step explanation:

Given y varies directly as x and inversely as the square of z then the equation relating them is

y = [tex]\frac{kx}{z^2}[/tex] ← k is the constant of variation

To find k use the condition y = 52, x = 16, z = 2

k = [tex]\frac{yz^2}{x}[/tex] = [tex]\frac{52(4)}{16}[/tex] = 13

y = [tex]\frac{13x}{z^2}[/tex] ← equation of variation

When x = 18 and z = 3, then

y = [tex]\frac{13(18)}{9}[/tex] = 26

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