eSar6ah8mogullissere eSar6ah8mogullissere

25-05-2016
Mathematics

contestada

What is the exact value of x in the exponential equation 2^8x − 3 = 7?

x = log4/8log2
x = 1/8log2
x= 5/8
x =log5/8

Respuesta :

25-05-2016

Hello,

2^(8x)-3=7
==>2^(8x)=10
==>8x log (2)=log(10)
==>8x log(2)=1

==>x=1/(8*log(2))
With parenthesis on the denominator, the answer is B.

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