Answer:
[tex]f(\frac{2}{9})=1[/tex]
Step-by-step explanation:
we have
[tex]f(x)=3x+\frac{1}{3}[/tex]
we know that
f(2/9) is the value of the function f(x) when the value of x is equal to 2/9
so
For x=2/9
substitute the value of x in the function and solve for f(x)
[tex]f(x)=3(\frac{2}{9})+\frac{1}{3}[/tex]
[tex]f(x)=\frac{2}{3}+\frac{1}{3}[/tex]
[tex]f(x)=\frac{3}{3}[/tex]
[tex]f(x)=1[/tex]
therefore
[tex]f(\frac{2}{9})=1[/tex]
