VannothyZacJo6ell
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  • 21-06-2016
  • Chemistry
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Mole of Al 3.26*10^24 atoms of Al

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gesubakieva
gesubakieva gesubakieva
  • 21-06-2016
n=N/Na=3.26*10^24/6.02*10^23=5.41mol.
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