Answer:
Step-by-step explanation:
Essentially, begin by flipping the x and y terms:
x = (1 - 2y)^2 + 5
Then, solve for y:
[tex]\ x = (1-2y)^2 + 5\\\sqrt{x-5} = 1 - 2y\\\sqrt{x-5} - 1 = 2y\\\frac{\sqrt{x-5} - 1}{2} = y^-1\\[/tex]
Because we know there is only 1 y-value for any given x-value, the inverse of the given function is also a function.
