Answer:
A)cosx(4sinx-1)=0
Step-by-step explanation:
The given equation is
[tex]2 \sin(2x) = \cos(x) [/tex]
We equate everything to zero to get:
[tex]2 \sin(2x) - \cos(x) = 0[/tex]
Use the double angle property, to get:
[tex]2 (2\sin(x) \: \cos(x) ) - \cos(x) = 0[/tex]
This implies that:
[tex] \cos x(4\sin \: x - 1) = 0[/tex]
The correct answer is A
