Answer:
see explanation
Step-by-step explanation:
The error lies in different bases being used, that is for 64 base 4 has been used and for 16 base 2 has been used.
The bases on both sides should be the same, that is
[tex]\frac{1}{64}[/tex] = [tex]16^{2a}[/tex] ( using base 4 to represent both numbers )
[tex]4^{-3}[/tex] = [tex]}(4^2)^{2a}[/tex]
[tex]4^{-3}[/tex] = [tex]4^{4a}[/tex]
Since bases on both sides are equal, equate the exponents
4a = - 3 ( divide both sides by 4 )
a = - [tex]\frac{3}{4}[/tex]
