26-02-2020
Mathematics

contestada

If 0° < ø < 90°, and sin 0 = 20/29, what is the value of csc(-0)?

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jimrgrant1 jimrgrant1

26-02-2020

Answer:

[tex]\frac{29}{20}[/tex]

Step-by-step explanation:

Using the trigonometric identity

csc x = [tex]\frac{1}{sinx}[/tex]

Given

sinΘ = [tex]\frac{20}{29}[/tex], then

cscΘ = [tex]\frac{1}{\frac{20}{29} }[/tex] = [tex]\frac{29}{20}[/tex]

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