KSizzle1998 KSizzle1998
  • 26-02-2020
  • Mathematics
contestada

Find θ, 0° ≤ θ < 360°, given the following information.
sin θ = − 1/2 and θ in QIII
θ = _________°

Respuesta :

jimrgrant1 jimrgrant1
  • 26-02-2020

Answer:

210°

Step-by-step explanation:

Given

sinΘ = - [tex]\frac{1}{2}[/tex]

Note taken the inverse sine of the positive value of the ratio, gives the related acute angle, that is

Θ = [tex]sin^{-1}[/tex]([tex]\frac{1}{2}[/tex] ) = 30° ← related acute angle

Thus the required angle in the third quadrant is

Θ = 180° + 30° = 210°

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