Answer:
940 J
Explanation:
This is a calorimtetry excersie where you apply the formula
Q = C . m . ΔT
We only have 2 data from here, C and ΔT (from the solution)
C → 3.97 J/g°C
ΔT → 2.3°C
We determine the solution's mass by density:
1.03 g/mL = Solution mass / Solution volume
We assume the HCl as the solution volume → 100 mL
1.03 g/mL . 100 mL = 103 g → solution's mass
We replace data: Q = 103 g . 3.97 J/g°C . 2.3°C → 940.4 J
