For this case we must find the distance between the points:
[tex](x_ {1}, y_ {1}): (- 6,8)\\(x_ {2}, y_ {2}) :( 6,3)[/tex]
By definition, the distance between two points is found by:
[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]
Substituting the points:
[tex]d = \sqrt {(6 - (- 6)) ^ 2+ (3-8) ^ 2}\\d = \sqrt {(6 + 6) ^ 2 + (- 5) ^ 2}\\d = \sqrt {144 + 25}\\d = \sqrt {169}\\d = 13[/tex]
So the distance is 13 units
Answer:
13 units
