emelynbrunson emelynbrunson
  • 24-03-2020
  • Mathematics
contestada

b) y = log2 (4" - 4)
find the inverse of this equation

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 02-04-2020

Answer:

[tex]y = \frac{1}{4} \times {2}^{x} - 1[/tex]

Step-by-step explanation:

Assuming the given logarithmic equation is

[tex]y = \log_{2}( {4}{x } - 4) [/tex]

We interchange x and y to get:

[tex]x= \log_{2}( {4}{y} - 4) [/tex]

We solve for y now:

[tex] {2}^{x} = {4}{y} - 4[/tex]

We add 4 to both sides to get;

[tex] {2}^{x} + 4 = 4y[/tex]

Divide through by 4:

[tex]y = \frac{1}{4} \times {2}^{x} - 1[/tex]

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