Answer:
Step 1: Solve for x in the first equation
[tex]3x-8+8\leq 23+8[/tex]
[tex]3x\leq 31[/tex]
[tex]3x/3\leq 31/3[/tex]
[tex]x\leq \frac{31}{3}[/tex]
Step 2: Solve for x in the second equation
[tex]-4x + 26-26 \geq 6-26[/tex]
[tex]-4x\geq -20[/tex]
[tex]-4x/-4\geq -20/-4[/tex]
Since you divide by a negative, you must flip the sign.
[tex]x\leq 5[/tex]
