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The force F (in newtons) of a hydraulic cylinder in a press is proportional to the square of sec x where x is the distance (in meters) that the cylinder is extended in its cycle. The domain of F is [0, π/3], and F(0) = 700.

Respuesta :

Answer:

[tex]F(x)=700*sec^2(x)[/tex]

Step-by-step explanation:

If the the force F is proportional to the square of sec x, the force F is equal to:

[tex]F(x)=k*sec^2(x)[/tex]

Where k is a constant.

Now, to find k, we are going to use:

[tex]F(0)=700[/tex]

So, if we replace x by 0 on the first equation, we get:

[tex]F(0)=k*sec^2(0)\\F(0)=k\\F(0)=k=700[/tex]

It means that k is equal to 700, so F as a function of x is equal to:

[tex]F(x)=700*sec^2(x)[/tex]

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