Answer:
[tex]x^2-12x+27 =0[/tex]
Step-by-step explanation:
Given a Parabola that intersects the x-axis at x=3 and x=9.
I presume you want to determine the equation of the parabola.
You can use this form:
Given roots of a parabola, the equation of the parabola is derived using the formula:
[tex]x^2-($Sum of Roots)x+Product of Roots =0\\Since roots are 3 and 9, the equation becomes:\\x^2-(3+9)x+(3X9) =0\\x^2-12x+27 =0[/tex]
The equation of the parabola is:
[tex]x^2-12x+27 =0[/tex]
