madisonhofstaedter madisonhofstaedter
  • 24-04-2020
  • Chemistry
contestada

How many L of 0.75 M Ca(OH)2(aq) are needed in order to have 5.5 mol of Ca(OH)2?

Respuesta :

PollyP52 PollyP52
  • 24-04-2020

Answer:

7 1/3 L.

Explanation:

1 liter of 0.75 M Ca(OH)2 aq contains 1 mole of Ca(OH)2.

By proportion that would be  5.50 / 0.75 L

= 7 1/3 L.

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