Answer:
[tex]\frac{16f^3}{3}[/tex]
Step-by-step explanation:
[tex]\frac{4f^{2} }{3}[/tex]÷ [tex]\frac{1}{4f}[/tex] = [tex]\frac{4f^{2} }{3(\frac{1}{4f})}[/tex] = [tex]\frac{4f^2(4f)}{3}[/tex] =[tex]\frac{16f^3}{3}[/tex]
