sandramtz1212 sandramtz1212

25-04-2020
Chemistry

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What is the concentration of hydroxide in a solution with a pOH of 9.8?
ph+pOH=14 [OH-]=10^-pOH

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SvetkaChem SvetkaChem

25-04-2020

Answer:

1.6*10^(-10) M

Explanation:

pOH = 9.8

[OH-]=10^{-log(pOH)} = 10^(-9.8) = 1.6*10^(-10)

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