Answer: 1 x 10∧-4
Explanation:
In other for us to get the OH- concentration,we must first get the pOH.
pH + pOH = 14
pOH = 14 - pH; 14 - 10 = 4
From the formular for finding pOH, we know; pOH= - Log [ OH-]
∴ [ OH-] = Anti -log of 4
= 10∧-4 = 0.0001
= 1 x 10∧-4
