segbawudeladem
segbawudeladem segbawudeladem
  • 24-06-2020
  • Mathematics
contestada

make P the subject of Pt²=2x-Pm a 2

Respuesta :

Hrishii
Hrishii Hrishii
  • 24-06-2020

Answer:

[tex] p = \frac {2x}{(2t^2 +m)} [/tex]

Step-by-step explanation:

[tex]p {t}^{2} = \frac {2x - pm}{2} \\

2pt^2 = 2x - pm\\

2pt^2 +pm= 2x \\

p(2t^2 +m) =2x\\\\

\huge\purple {\boxed {p = \frac {2x}{(2t^2 +m)}}}

\\ [/tex]

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