kyemonthant130803 kyemonthant130803

23-08-2020
Mathematics

contestada

solve the equation2.2^2x-7×2^x-4=0.

Respuesta :

mhanifa mhanifa

23-08-2020

Answer:

2

Step-by-step explanation:

2×2^2x - 7×2^x - 4=0
2×(2^x)^2 - 7×2^x - 4 = 0

Substitute 2^x = y, where y>0

Then we get quadratic equation:

2y^2 - 7y - 4 = 0

Solving this, we get y = 4 as positive root, so;

y = 4
2^x = 4
2^x = 2^2
x = 2

Answer is 2

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