Answer:
The velocity after 6 m while moving at 10 m/s² ≈ 10.95 m/s
Explanation:
The given parameters are;
The given distance of the sack movement = 6 m
The acceleration, a of the sack = 10 m/s²
The velocity of the is given from the relation;
v² = u² + 2×a×s
Where;
u =The initial velocity = 0
Which gives;
v² = 2×a×s
v² = 2×10×6 - 120
v = √120 = 2·√30 m/s
The velocity after 6 m while moving at 10 m/s² is 2·√30 m/s or approximately equal to 10.95 m/s.
