Answer:
The object will hit the ground at 882.77 m from the lunch
Explanation:
we are to find the range of the motion
What is range?
It is the distance from the point of projection to the point where the object hits the ground
R=(v^2sin2θ)/g
Given data
v= 100 m/s
θ= 30 degree
g= 9.81 m/s^2
Substituting to find the R we have
R= 100^2 *sin(2*30)/9.81
R= (10000*0.866)9.81
R= 8660/9.81
R= 882.77 m
