Answer:
[tex]\bold{[g\circ f](x) = 2x^2-13x+2}[/tex]
Step-by-step explanation:
[tex]{}[g\circ f](x) = g[f(x)] \\\\{} [g\circ f](x)= g(x-5)\\\\{} [g\circ f](x) = 2(x-5)^2+7(x-5)-13\\\\{} [g\circ f](x) = 2(x^2-10x+25)+7x-35-13\\\\{} [g\circ f](x) = 2x^2-20x+50+7x-48\\\\{} [g\circ f](x) = 2x^2-13x+2[/tex]
