landrochedaniel landrochedaniel
  • 23-10-2020
  • Mathematics
contestada

4x^2-5<_9
How to solve less than or equal to

Respuesta :

jtursunboyev17072001
jtursunboyev17072001 jtursunboyev17072001
  • 25-10-2020

[tex]\begin{bmatrix}\mathrm{Solution:}\:&\:-\sqrt{\frac{7}{2}}\le \:x\le \sqrt{\frac{7}{2}}\:\\ \:\mathrm{Decimal:}&\:-1.87082\dots \le \:x\le \:1.87082\dots \\ \:\mathrm{Interval\:Notation:}&\:\left[-\sqrt{\frac{7}{2}},\:\sqrt{\frac{7}{2}}\right]\end{bmatrix}[/tex]

[tex]\frac{4x^2}{4}\le \frac{14}{4}[/tex]

[tex]x^{2}[/tex]≤[tex]\frac{7}{2\\}[/tex]

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