Answer:
2nd option
Step-by-step explanation:
Solve the parentheses first;
[tex](\frac{2}{5}x +\frac{5}{8}) +(\frac{1}{5}x- \frac{1}{4} )\\\\\frac{2}{5}x+\frac{5}{8}+\frac{1}{5}x-\frac{1}{4}= \frac{2}{5}x+\frac{1}{5}x+\frac{5}{8}-\frac{1}{4}\\\\\frac{2}{5}x+\frac{1}{5}x=\frac{2x+x}{5}=\frac{3x}{5} = \frac{3}{5}x \\\\\frac{5}{8}-\frac{1}{4}=\frac{5-2}{8} =\frac{3}{8}\\\\\frac{3}{5}x+\frac{3}{8}[/tex]
