Answer:
2 solutions
Step-by-step explanation:
Given
2x² + 3x - 5 ( to solve the quadratic equate it to zero )
2x² + 3x - 5 = 0 ← in standard form
(2x + 5)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = - [tex]\frac{5}{2}[/tex]
x - 1 = 0 ⇒ x = 1
The 2 solutions are x = - [tex]\frac{5}{2}[/tex] , x = 1
