be7lldebr5ebeccar be7lldebr5ebeccar
  • 22-10-2016
  • Chemistry
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determine how many moles are present in 523.46g of glucose, c6h12o6

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Willchemistry
Willchemistry Willchemistry
  • 23-10-2016

1 mole C6H12O6 -------------- 180.15 g
? moles C6H12O6 ------------ 523.46 g

523.46 x 1 / 180.15 => 2.905 moles
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