MindTrickery
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  • 23-01-2021
  • Mathematics
contestada

Let r and s be the roots of x^2 - 6x + 2 = 0. Find (r - s)^2.

Respuesta :

bluegreen24
bluegreen24 bluegreen24
  • 24-01-2021

Answer: [tex](r-s)^{2} = 28[/tex]

Step-by-step explanation:

  • [tex]x^{2} -6x+9=-2+9[/tex]
  • [tex](x-3)^{2}=7[/tex]
  • [tex](x-3)= -\sqrt{7}[/tex] or [tex]\sqrt{7}[/tex] <-- there's no plus/minus sign.
  • [tex](x-3) = -\sqrt{7}[/tex]
  • [tex]x = 3 -\sqrt{7}[/tex] <-- root.
  • [tex](x-3) = \sqrt{7}[/tex]
  • [tex]x = 3+\sqrt{7}[/tex] <-- root.
  • [tex][(3-\sqrt{7})-(3+\sqrt{7})]^{2}[/tex]
  • [tex](3-\sqrt{7} -3 - \sqrt{7})^{2}[/tex] <-- don't forget to distribute the negative.
  • [tex](-2\sqrt{7})^{2}[/tex]
  • [tex](4)(7)[/tex]
  • [tex]28[/tex]
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