Answer:
x = - [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
Assuming you mean
[tex]16^{x}[/tex] = [tex]\frac{1}{64}[/tex]
note that 16 = 4² and 64 = 4³ , so
[tex](4^{2} )^{x}[/tex] = [tex]\frac{1}{4^{3} }[/tex]
[tex]4^{2x}[/tex] = [tex]4^{-3}[/tex]
Since the bases on both sides are equal, both 4, then equate exponents
2x = - 3 ( divide both sides by 2 )
x = - [tex]\frac{3}{2}[/tex] ( = - 1.5 )
