Answer:
the work done is 150 J.
Explanation:
Given;
heat energy from the hot reservoir, QH = 250 J
heat energy from the cold reservoir, Qc = 100 J
Let the work done = W
The work done is calculated as follows;
W = QH - Qc
W = 250 J - 100 J
W = 150 J
Therefore, the work done is 150 J.
