mistymcclanahan31 mistymcclanahan31
  • 26-04-2021
  • Mathematics
contestada


One number is 4 less than a second number. Twice the second number is 13 less than 5 times the first. Find the two numbers.

Respuesta :

devishri1977
devishri1977 devishri1977
  • 27-04-2021

Answer:

7 , 11

Step-by-step explanation:

Let the second number be 'x'

the first number = x - 4

Twice the second number : 2*x = 2x

5times first = 5*(x -4) = 5*x - 5*4 = 5x - 20

13 less than 5 times the first = 5x - 20 - 13 = 5x - 33

5x - 33 = 2x

Add 33 to both sides

5x - 33 + 33 = 2x +33

5x = 2x + 33

Subtract '2x'from both sides

5x - 2x = 2x - 2x + 33

3x = 33

Divide both sides by 3

[tex]\frac{3x}{3}=\frac{33}{3}[/tex]

x = 11

First number = x - 4 = 11 - 4 = 7

The numbers are 7 , 11

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