Answer:
12\sqrt{2}
Step-by-step explanation:
To get the hypotenuse, first we need to get the side length of the square
Area of the square = L²
16\sqrt{3} = L²
L = 4×3
L = 12
Using pythagiras theorem to get the hypotenuse
Hyp² = 12²+12²
Hyp² = 144+144
Hyp² = 288
Hyp = \sqrt {288}
Hyp = 12\sqrt{2}
Hence the hypotenuse of the square is 12\sqrt{2}
