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25-08-2021
Chemistry

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How many moles of Al2O3 are contained in 45.1 g of Al2O3?

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Tedrick0011 Tedrick0011

25-08-2021

Answer:

0.44mol

Explanation:

1mol/102g=xmol/45.1g

-> x=(45.1x1)/102

x=0.44mol

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